## Public projects 2

Project tutorial by Sumit Aich

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#### Low Cost Accurate 3D Positioning

Project tutorial by Sumit Aich

• 4,813 views
• 8 respects

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## Respected projects 2

Project tutorial by Sumit Aich

• 2,911 views
• 18 respects

#### Low Cost Accurate 3D Positioning

Project tutorial by Sumit Aich

• 4,813 views
• 8 respects

• ##### Low Cost Accurate 3D Positioning20 days ago

If you face any issues while reconstructing this water-based 3D sensor, feel free to ask here.

• ##### Low Cost Accurate 3D Positioning20 days ago

Many people are confused regarding the use of slant electrodes instead of perpendicular electrodes in my 3D sensor.
Well, here's the deal.
In case of cuboid, the normal vector to the 3 planes will be parallel to the horizontal base. So the angle between normal vector and z-axis equals pi/2 radians. So the 'n' direction cosine of normal vector equals 0. So the 3rd column of the matrix of direction cosines of the 3 planes is a column of 0s . The determinant of a matrix is 0 if any of its rows or columns are 0. So matrix 'A' is a singular matrix. For a non-homogeneous system of 3 unknowns, if matrix 'A' is singular, it implies that the system of equations will have either no solution or infinity number of solutions. Since, 3rd column of matrix is 0, so its matrix of co-factors is a null matrix. Transpose of a null matrix is a null matrix. So adj(A) is a null matrix. So (adj(A)).B is also a null matrix. This will prove that the system of equations is consistent and has infinity number of solutions.
This issue is not present in case of slant electrodes.

• ##### DIY \$0 Water Trackpad21 days ago

the reason is that the current density vector must be normal to the end planes at all points on the plane. This can be made possible only if the ENTIRE end plane is an equipotential surface. Since aluminum has negligible resistivity compared to water, it acts as an equipotential surface and must cover the entire end planes.